10/8/2021

Unit 3 Derivative Rules Of Compositesap Calculus

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The Derivative tells us the slope of a function at any point.

There are rules we can follow to find many derivatives.

Day 3: The Chain Rule (continued) Day 4: Quiz (Topic 3.1) Day 5: Implicit Differentiation. Day 6: Implicit Differentiation (continued) Day 7: Differentiating Inverse Functions. Day 8: Differentiating Inverse Trigonometric Functions. Day 9: Higher-order Derivatives and Derivative Strategies. Day 10: Review Day. Day 11: Unit 3 Test. Practicing Derivative Rules II. View study plan. 2550 north lake drive suite 2 milwaukee, wi 53211. About privacy contact. Search this site. Unit 3 Differentiation Rules Students will discover rules to differentiate various algebraic functions. These differentiation rules will help to analyze particular graphical features of functions in the upcoming units.

For example:

  • The slope of a constant value (like 3) is always 0
  • The slope of a line like 2x is 2, or 3x is 3 etc
  • and so on.

Here are useful rules to help you work out the derivatives of many functions (with examples below). Note: the little mark means 'Derivative of', and f and g are functions.

Common FunctionsFunction
Derivative
Constantc0
Linex1
axa
Squarex22x
Square Root√x(½)x
Exponentialexex
axln(a) ax
Logarithmsln(x)1/x
loga(x)1 / (x ln(a))
Trigonometry (x is in radians)sin(x)cos(x)
cos(x)−sin(x)
tan(x)sec2(x)
Inverse Trigonometrysin-1(x)1/√(1−x2)
cos-1(x)−1/√(1−x2)
tan-1(x)1/(1+x2)
RulesFunction
Derivative
Multiplication by constantcfcf’
Power Rulexnnxn−1
Sum Rulef + gf’ + g’
Difference Rulef - gf’ − g’
Product Rulefgf g’ + f’ g
Quotient Rulef/g(f’ g − g’ f )/g2
Reciprocal Rule1/f−f’/f2
Chain Rule
(as 'Composition of Functions')
f º g(f’ º g) × g’
Chain Rule (using ’ )f(g(x))f’(g(x))g’(x)
Chain Rule (using ddx )dydx = dydududx

'The derivative of' is also written ddx

So ddxsin(x) and sin(x)’ both mean 'The derivative of sin(x)'

Examples

Example: what is the derivative of sin(x) ?

From the table above it is listed as being cos(x)

It can be written as:

sin(x) = cos(x)

Or:

sin(x)’ = cos(x)

Power Rule

Example: What is x3 ?

The question is asking 'what is the derivative of x3 ?'

We can use the Power Rule, where n=3:

xn = nxn−1

x3 = 3x3−1 = 3x2

(In other words the derivative of x3 is 3x2)

So it is simply this:

3x^2'>
'multiply by power
then reduce power by 1'

It can also be used in cases like this:

Example: What is (1/x) ?

1/x is also x-1

We can use the Power Rule, where n = −1:

xn = nxn−1

x−1 = −1x−1−1

= −x−2

= −1x2

So we just did this:

-x^-2'>
which simplifies to −1/x2

Multiplication by constant

Example: What is 5x3 ?

the derivative of cf = cf’

the derivative of 5f = 5f’

We know (from the Power Rule):

x3 = 3x3−1 = 3x2

So:

5x3 = 5x3 = 5 × 3x2 = 15x2

Sum Rule

Example: What is the derivative of x2+x3 ?

The Sum Rule says:

the derivative of f + g = f’ + g’

Unit 3 derivative rules of compositesap calculus solver

So we can work out each derivative separately and then add them.

Using the Power Rule:

  • x2 = 2x
  • x3 = 3x2

And so:

the derivative of x2 + x3 = 2x + 3x2

Difference Rule

Unit 3 Derivative Rules Of Compositesap Calculus

It doesn't have to be x, we can differentiate with respect to, for example, v:

Example: What is (v3−v4) ?

The Difference Rule says

the derivative of f − g = f’ − g’

So we can work out each derivative separately and then subtract them.

Using the Power Rule:

  • v3 = 3v2
  • v4 = 4v3

And so:

the derivative of v3 − v4 = 3v2 − 4v3

Sum, Difference, Constant Multiplication And Power Rules

Example: What is (5z2 + z3 − 7z4) ?

Using the Power Rule:

  • z2 = 2z
  • z3 = 3z2
  • z4 = 4z3

And so:

(5z2 + z3 − 7z4) = 5 × 2z + 3z2 − 7 × 4z3 = 10z + 3z2 − 28z3

Product Rule

Example: What is the derivative of cos(x)sin(x) ?

The Product Rule says:

the derivative of fg = f g’ + f’ g

In our case:

  • f = cos
  • g = sin

We know (from the table above):

  • cos(x) = −sin(x)
  • sin(x) = cos(x)

So:

the derivative of cos(x)sin(x) = cos(x)cos(x) − sin(x)sin(x)
= cos2(x) − sin2(x)

Quotient Rule

To help you remember:

(fg)’ = gf’ − fg’g2

The derivative of 'High over Low' is:

'Low dHigh minus High dLow, over the line and square the Low'

Example: What is the derivative of cos(x)/x ?

In our case:

  • f = cos
  • g = x

We know (from the table above):

  • f' = −sin(x)
  • g' = 1

So:

the derivative of cos(x)x = Low dHigh minus High dLowover the line and square the Low

= x(−sin(x)) − cos(x)(1)x2

= −xsin(x) + cos(x)x2

Reciprocal Rule

Example: What is (1/x) ?

The Reciprocal Rule says:

the derivative of 1f = −f’f2

With f(x)= x, we know that f’(x) = 1

So:

Rules

the derivative of 1x = −1x2

Which is the same result we got above using the Power Rule.

Chain Rule

Example: What is ddxsin(x2) ?

sin(x2) is made up of sin() and x2:

  • f(g) = sin(g)
  • g(x) = x2

The Chain Rule says:

the derivative of f(g(x)) = f'(g(x))g'(x)

The individual derivatives are:

Unit 3 Derivative Rules Of Compositesap Calculus Integrals

  • f'(g) = cos(g)
  • g'(x) = 2x

So:

ddxsin(x2) = cos(g(x)) (2x)

= 2x cos(x2)

Unit 3 Derivative Rules Of Compositesap Calculus 2nd Edition

Another way of writing the Chain Rule is: dydx = dydududx

Let's do the previous example again using that formula:

Example: What is ddxsin(x2) ?

dydx = dydududx

Have u = x2, so y = sin(u):

ddx sin(x2) = ddusin(u)ddxx2

Differentiate each:

Unit 3 Derivative Rules Of Compositesap Calculus Calculator

ddx sin(x2) = cos(u) (2x)

Substitue back u = x2 and simplify:

ddx sin(x2) = 2x cos(x2)

Same result as before (thank goodness!)

Another couple of examples of the Chain Rule:

Example: What is (1/cos(x)) ?

1/cos(x) is made up of 1/g and cos():

  • f(g) = 1/g
  • g(x) = cos(x)

The Chain Rule says:

the derivative of f(g(x)) = f’(g(x))g’(x)

The individual derivatives are:

  • f'(g) = −1/(g2)
  • g'(x) = −sin(x)

So:

(1/cos(x))’ = −1/(g(x))2 × −sin(x)

= sin(x)/cos2(x)

Note: sin(x)/cos2(x) is also tan(x)/cos(x), or many other forms.

Example: What is (5x−2)3 ?

The Chain Rule says:

the derivative of f(g(x)) = f’(g(x))g’(x)

Unit 3 Derivative Rules Of Compositesap Calculus Solver

(5x-2)3 is made up of g3 and 5x-2:

Unit 3 derivative rules of compositesap calculus calculator
  • f(g) = g3
  • g(x) = 5x−2

The individual derivatives are:

  • f'(g) = 3g2 (by the Power Rule)
  • g'(x) = 5

So:

(5x−2)3 = 3g(x)2 × 5 = 15(5x−2)2

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